Chemical Reaction: Carbon C with Sulfur Dioxide SO2

Calculating the Grams of CS2 Produced

Step 1: Determine the molar mass of CS2.

The molar mass of CS2 (Carbon disulfide) is:

Carbon (C) = 12.01 g/mol

Sulfur (S) = 32.07 g/mol

Molar mass of CS2 = (1 * 12.01) + (2 * 32.07) = 76.15 g/mol

Step 2: Calculate the moles of CS2 produced from 6.00 moles of C.

From the balanced chemical equation, we see that 3 moles of C produce 1 mole of CS2.

So, 6.00 moles of C will produce:

6.00 moles C * (1 mol CS2 / 3 mol C) = 2.00 moles CS2

Step 3: Convert moles of CS2 to grams of CS2.

Using the molar mass of CS2 calculated earlier:

2.00 moles CS2 * 76.15 g/mol = 152.30 grams of CS2

Therefore, when 6.00 moles of Carbon reacts completely with an excess amount of SO2 gas, 152.30 grams of CS2 are produced.

← A gas volume calculation problem ideal gas law Lab 6 chemical reactions of copper and percent yield →

More Posts: