Chemical Reaction: From Copper to Zinc

What is the resulting atom from a nuclide of a Copper that absorbs a positron?

The resulting atom from a nuclide which absorbs a positron is ⁶⁴ Zn ₃₀.

The correct answer is ⁶⁴ Zn ₃₀.

Positron is ⁰e₊₁ particle. When it is absorbed, the atomic number increases by 1 but the atomic mass remains the same. The given nuclide is ⁶⁴ Cu₂₉. In this nuclide, the atomic mass is 64, and the atomic number is 29.

When the ⁶⁴ Cu₂₉ absorbs one positron, the atomic number increases by 1 to atomic number 30. Since atomic number 30 corresponds to Zinc, the resulting atom from the reaction is ⁶⁴ Zn ₃₀. The chemical reaction can be represented as follows:

⁶⁴ Cu₂₉ + ⁰e₊₁ → ⁶⁴ Zn ₃₀

Therefore, the atomic number of copper is 29, and the atomic number of zinc is 30. The positron, ⁰e₊₁, remains the same in the reaction while the atomic number increases to signify the production of ⁶⁴ Zn ₃₀.

Chemical reactions involve the conversion of reactants into products, resulting in the formation of new substances.