What is the relationship between pressure and volume in Boyle's law? Based on the data given: A sample of carbon dioxide occupies a volume of 3.50 L at 1.20 atm. If the volume were decreased to 2.00 L, what pressure would the gas exert? Answer: The pressure would be 2.1 atm Boyle's law states that there is an inverse relationship between pressure and volume of a gas at constant temperature. The formula for Boyle's law is given by: P1V1 = P2V2 Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume respectively. By using this formula, we can calculate the new pressure: P2 = (P1 * V1) / V2 Substitute the values from the data: (3.5 L * 1.2 atm) / 2 L = 2.1 atm Therefore, the gas would exert a pressure of 2.1 atm if the volume is decreased to 2.00 L. This shows the relationship between pressure and volume as described in Boyle's law.

Question

What is the relationship between pressure and volume in Boyle's law?     Based on the data given: A sample of carbon dioxide occupies a volume of 3.50 L at 1.20 atm. If the volume were decreased to 2.00 L, what pressure would the gas exert?       Answer:     The pressure would be 2.1 atm      Boyle's law states that there is an inverse relationship between pressure and volume of a gas at constant temperature. The formula for Boyle's law is given by:     P1V1 = P2V2     Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume respectively. By using this formula, we can calculate the new pressure:     P2 = (P1 * V1) / V2     Substitute the values from the data:     (3.5 L * 1.2 atm) / 2 L = 2.1 atm     Therefore, the gas would exert a pressure of 2.1 atm if the volume is decreased to 2.00 L. This shows the relationship between pressure and volume as described in Boyle's law.

Marcel · Answer

Answer:     The pressure would be 2.1 atm      Boyle's law states that there is an inverse relationship between pressure and volume of a gas at constant temperature. The formula for Boyle's law is given by:     P1V1 = P2V2     Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume respectively. By using this formula, we can calculate the new pressure:     P2 = (P1 * V1) / V2     Substitute the values from the data:     (3.5 L * 1.2 atm) / 2 L = 2.1 atm     Therefore, the gas would exert a pressure of 2.1 atm if the volume is decreased to 2.00 L. This shows the relationship between pressure and volume as described in Boyle's law.

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What is the relationship between pressure and volume in Boyle's law?

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