How to Make 0.222 M Nitric Acid Solution?
What is the required concentration of nitric acid to make 225 mL of 0.222 M solution?
How much concentrated nitric acid is required to achieve the desired solution?
Answer:
To make a 0.222 M solution of nitric acid with a volume of 225 mL, you will need 3.12 mL of 16 M nitric acid.
When preparing a solution of a specific concentration, it is important to calculate the amount of concentrated solution needed to achieve the desired concentration. In this scenario, the task is to make a 0.222 M solution of nitric acid with a total volume of 225 mL.
The formula used to calculate the volume of concentrated nitric acid required is:
V2 = (M1 * V1) / M2
Where:
- V2 is the volume of concentrated nitric acid needed
- M1 is the desired concentration of nitric acid (0.222 M)
- V1 is the total volume of the solution (225 mL)
- M2 is the concentration of the concentrated nitric acid (16 M)
By substituting the values into the formula, we get:
V2 = (0.222 M * 225 mL) / 16 M = 3.12 mL
Therefore, you will need 3.12 mL of 16 M nitric acid to prepare 225 mL of 0.222 M nitric acid solution. Make sure to measure accurately to achieve the desired concentration.