Optimistic Approach to Chemical Calculations: Weight of Aluminum Sulfate Obtained

How to Calculate the Weight of Aluminum Sulfate Obtained from Impure Aluminum?

Given 50g of aluminum with 10% impurities and a 70% yield, what is the weight of aluminum sulfate obtained?

Calculation of Aluminum Sulfate Weight

Based on the data provided, we can calculate the weight of aluminum sulfate obtained through a series of steps:

Firstly, we need to determine the mass of pure aluminum present in the 50g sample. Since the aluminum is 90% pure (10% impurities), the mass of pure aluminum is 50g x 0.9 = 45g.

Next, we calculate the moles of aluminum using its molar mass: Molar mass of Al = 27 g/mol. Moles of Al = 45g Al / 27 g/mol = 1.67 mol.

Considering the 70% yield of the reaction, only 70% of the aluminum will react to form aluminum sulfate. Thus, the moles of aluminum sulfate obtained will be: Moles of Al2(SO4)3 = 1.67 mol x 70% = 1.17 mol.

Calculating the weight of aluminum sulfate involves multiplying the moles by its molar mass: Molar mass of Al2(SO4)3 = (2 x 27 g/mol) + (3 x (32 g/mol + 4 x 16 g/mol)) = 342 g/mol. Weight of Al2(SO4)3 = 1.17 mol x 342 g/mol = 399.14 g.