A Student Jumping Off a Cliff: Calculating Airborne Time

The time in which the student was airborne

A student jumps off of a cliff into a river 25.9 m below. If the student landed 20.7 m horizontally away from where they jumped, how much time was the student airborne?

How do I determine the time?

From motion under gravity, we understand that the time and height are related according to the following formula:

h = ½gt²

Where:

h is the height

g is the acceleration due to gravity

t is the time

With the above formula, we can obtain the time the student was airborne. Details below:

Height (h) = 25.9 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = ?

h = ½gt²

25.9 = ½ × 9.8 × t²

25.9 = 4.9 × t²

Divide both sides by 4.9

t² = 25.9 / 4.9

Take the square root of both sides: t = √(25.9 / 4.9)

t = 2.3 s

Thus, we can conclude that the time taken is 2.3 seconds.

The time in which the student was airborne, given that the student jumped off the cliff into a river 25.9 m below is 2.3 seconds. How do you calculate the time the student was airborne?

From the motion under gravity, we use the formula h = ½gt² to determine the time the student was airborne. By substituting the height, acceleration due to gravity, and solving for time, we find that the student was airborne for 2.3 seconds.