A Student Throwing a Ball from a Balcony

What is the velocity of the ball as it strikes the ground?

Answer:

20.65 m/s Explanation: When the student throws the ball vertically downward from a height of 15.6 m above the street with an initial velocity of 10.7 m/s, we can calculate the velocity of the ball as it strikes the ground using the equations of motion. Using the third equation of motion, which is v² - u² = 2ah, where: - h = 15.6 m (height) - u = 10.7 m/s (initial velocity) - a = 10 m/s² (acceleration due to gravity) Substituting the values into the equation: v² - (10.7)² = 2(10)(15.6) v² - 114.49 = 312 v² = 426.49 v = √426.49 v = 20.65 m/s Therefore, the velocity of the ball as it strikes the ground is 20.65 m/s.
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