Calculating Resistance of a Light Bulb in an Automobile
Resistor Power Calculation
The resistance of the light bulb is R = 2.4 Ω.
We can use the formula for power in terms of voltage and resistance to solve for the resistance of the light bulb.
The power (P) dissipated by a resistor can be calculated using the formula:
P = V² / R
Where:
P is the power (60 watts in this case)
V is the voltage (12 volts)
R is the resistance (what we're trying to find)
Rearranging the formula to solve for resistance:
R = V² / P
Substitute the given values:
R = (12 volts)² / 60 watts = 144 / 60 Ω = 2.4 Ω
Question:
What is the resistance of the light bulb in an automobile when it dissipates 60 watts connected to a 12 volt battery?
Answer:
The resistance of the light bulb in this scenario is calculated to be 2.4 Ω.