Exciting Physics Challenge: Gas Pressure Calculation!

How to Calculate the Final Pressure of Gas in a Cylindrical Tank?

Answer: The final value of the pressure is 0.89 atm

Are you ready for an exciting physics challenge? Let's dive into the world of gas pressure calculation in a cylindrical tank with a tight-fitting piston!

In this scenario, we have a tank that originally contains 0.120 of air at a pressure of 3.50 atm. The piston is slowly pulled out until the volume of the gas is increased to 0.430. With the temperature remaining constant, we need to determine the final value of the pressure.

To solve this problem, we can use the formula for constant temperature:

[(P1 * V1) / (nR)] = [(P2 * V2) / (nR)]

Given that the temperature is constant, we can simplify the equation to:

P1 * V1 = P2 * V2

Plugging in the values, we get:

P2 = (P1 * V1) / V2 = (0.120 * 3.50) / 0.430 atm = 0.89 atm

Therefore, the final value of the pressure in the cylindrical tank is 0.89 atm. Congratulations on mastering this physics challenge!

← Understanding velocity of balls thrown upward and downward What happens when one lamp in a three lamp parallel circuit burns out →