Hydrostatic Force Calculation on Window with Semi-Circle Diameter

Calculating Hydrostatic Force on Window

The hydrostatic force on the window with a semi-circle diameter of 110 centimeters and a depth of 1.25 meters is 42,665.625 N. To find the hydrostatic force, follow these steps:
  1. Convert diameter to radius: Radius (r) = Diameter / 2 = 110 cm / 2 = 55 cm = 0.55 m
  2. Calculate the area of the semi-circle: Area (A) = (1/2)πr² = (1/2)π(0.55)² = 0.475625 m²
  3. Calculate the pressure at the center of the window: Pressure (P) = ρgh, where ρ (rho) is the density of water (1000 kg/m³), g is the gravitational acceleration (9.81 m/s²), and h is the depth (1.25 m). P = 1000 × 9.81 × 1.25 = 12,262.5 N/m²
  4. Multiply the pressure by the area to find the hydrostatic force: Force (F) = PA = 12,262.5 × 0.475625 = 42,665.625 N

If a different liquid with a different density is used instead of water, how would the hydrostatic force on the window change?

If a different liquid with a different density is used instead of water, the hydrostatic force on the window would change based on the density of the new liquid. The formula for hydrostatic force includes the density of the liquid, so a higher or lower density liquid would result in a different hydrostatic force exerted on the window.

← Understanding image formation using thin lens equation The area of the airy disk in diffraction pattern calculation →

More Posts: