The Velocity of a Ball Dropped from a Height of 19.6m

Calculating the Velocity of the Ball

If a ball is dropped from a height of 19.6m, what is the velocity with which the ball hits the ground?

Answer: V=√2hg

Distance/time=√2gh

19.6/t=√2×9.8×19.6

19.6/t=19.6

t=1sec

Explanation:

Given: y₀ = 19.6 m, y = 0 m, v₀ = 0 m/s, a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 19.6 m)

v = ±19.6 m/s

Since the ball is falling downwards, v = -19.6 m/s.

if a ball is dropped from a height of 19.6m, what is the velocity with which the ball hits the ground?

V=√2hg Distance/time=√2gh 19.6/t=√2×9.8×19.6 19.6/t=19.6 t=1sec -19.6 m/s Explanation: Given:y₀ = 19.6 m y = 0 m v₀ = 0 m/s a = -9.8 m/s² Find: v v² = v₀² + 2a (y − y₀) v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 19.6 m) v = ±19.6 m/s Since the ball is falling downwards, v = -19.6 m/s.