Understanding Energy in a Vertical Spring-Mass System

What are the forms of energy involved in a situation where a block of weight 10 N falls vertically due to gravity while attached to a spring with an elastic constant of 50 N/m, assuming no air resistance?

Explanation:

Step one:

Given data:

A block with a weight of 10 N,

Spring constant k = 50 N/m

Step two:

The form of energy involved in this situation is kinetic energy.

Step three:

From Hooke's law, F = kε

ε = F / k

ε = 10/50

ε = 0.2m

We can calculate the kinetic energy using the formula:

KE = 1/2kε^2

KE = 0.5 * 50 * (0.2)^2

KE = 0.5 * 50 * 0.04

KE = 1J

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